The first difference between Tn and Tn-1 where Tn= 688 is 88 if the quadratic sequence is defined as:2;12;28;50
It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
The quadratic sequence:
2, 12, 28, 50
a + b + c = 2
10, 16, 22 (first difference)
3a + b = 10
6, 6 (second difference)
2a = 6
a = 3
b = 1
c = -2
Tterm:
T(n) = 3n² + n - 2 = 688 (given)
After solving the quadratic equation:
n = 15, n = -46/3(n cannot be nagatve)
n = 15
n - 1 = 14
T(14) = 600
T(n) - T(n-1) = 688 - 600 = 88
Thus, the first difference between Tn and Tn-1 where Tn= 688 is 88 if the quadratic sequence is defined as:2;12;28;50
Learn more about the sequence here:
brainly.com/question/21961097
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