Taking into account the reaction stoichiometry, 2.405 moles of NaCl are formed when 127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.
In first place, the balanced reaction is:
2 FeCl+ 3 Na₂CO₂ → Fe₂(CO₃)₃ + 6 NaCl
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of the compounds is:
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
The following rule of three can be applied: if by reaction stoichiometry 318 grams of Na₂CO₂ form 6 moles of NaCl, 127.49 grams of Na₂CO₂ form how many moles of NaCl?
[tex]moles of NaCl=\frac{127.49 grams of Na_{2} CO_{2} x6 moles of NaCl }{318grams of Na_{2} CO_{2} }[/tex]
moles of NaCl= 2.405 moles
Then, 2.405 moles of NaCl are formed when 127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.
Learn more about the reaction stoichiometry:
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