The maximum amount of CaCO3 we can expect is 0.0180 mole x 100 g/mole = 1.80 g.
Given that:
There would be a precipitate of calcium carbonate from the reaction between sodium carbonate and calcium chloride.
The reaction is:
Na2CO3 (aq) + CaCl2(aq) → CaCO3 (s) + 2 NaCl (aq)
2.00 g CaCl2 x 1 mole/ 111 g CaCl2
= 0.0180 mole CaCl2
Mix it with 2.00 g Na2CO3 x 1 mole/ 106 g
= 0.0189 mole Na2CO3
The maximum amount of CaCO3 we can expect is 0.0180-mole x 100 g/mole = 1.80 g
Therefore, the 1.80 g is the theoretical (calculated) yield of CaCO3 in this example.
Read more about theoretical yield here:
https://brainly.com/question/25996347
#SPJ1
