The boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.
We must understand the issue with the river crossing in order to identify the solution.
[tex]\alpha =sin^{-1}(\frac{V_R}{V_B} )[/tex]
[tex]\alpha =sin{-1}(\frac{3}{5} )[/tex]
Thus, we can deduce that the boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.
Learn more about the velocity vector here:
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