The distance traveled by car A when they pass each other is 3,428.56 ft.
(Va)t - (Vb)t = d
where;
80t - (-60)t = 6000
80t + 60t = 6000
140t = 6000
t = 6000/140
t = 42.857 s
s = vt
s = 80 x 42.857
s = 3,428.56 ft
Thus, the distance traveled by car A when they pass each other is 3,428.56 ft.
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