We must mix 240 liters of the 51 % solution and 10 liters of the 26 % solutions to produce 250 liters of 50 % solution.
How to prepare a solution by using weighted averages
Herein we have to prepare a solution with fertilizers by mixing two different solutions. The amount needed of the 51 % solution can be found by weighted averages:
(50/100) · (250 L) = (51/100) · x + (26/100) · (250 - x)
50 · 250 = 51 · x + 26 · 250 - 26 · x
24 · 250 = 25 · x
x = 240
We must mix 240 liters of the 51 % solution and 10 liters of the 26 % solutions to produce 250 liters of 50 % solution.
To learn more on weighted averages: https://brainly.com/question/18554478
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