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Express the following linear equations in the form ax + by + c = 0 and indicate the values of a , b , c in each case :

i ) -2x + 3y = 6
ii) 2x = -5y​

Respuesta :

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

Question - 1 :

[tex]\qquad \sf  \dashrightarrow \: - 2x + 3y = 6[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 2x + 3y - 6[/tex]

[tex]\qquad \sf  \dashrightarrow \: (- 2)x + (3)y + (- 6)[/tex]

comparing it to general equation, we get :

  • [tex] \sf\dashrightarrow \: a = - 2[/tex]
  • [tex] \sf\dashrightarrow \: b = 3[/tex]
  • [tex] \sf\dashrightarrow \: c= - 6[/tex]

Similarly,

Question - 2 :

[tex]\qquad \sf  \dashrightarrow \: 2x = - 5y[/tex]

[tex]\qquad \sf  \dashrightarrow \: 2x + 5y = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: (2)x + (5)y + 0 = 0[/tex]

comparing it with general equation, we get :

  • [tex] \sf\dashrightarrow \: a = 2[/tex]
  • [tex] \sf\dashrightarrow \: b = 5[/tex]
  • [tex] \sf\dashrightarrow \: c = 0[/tex]

Step-by-step explanation:

i) -2x + 3y = 6

-2x + 3y +(-6) = 0

-2x + 3y - 6 = 0

Comparing this equation with ax + by + c = 0

  • a = -2
  • b = 3
  • c = 6

[ Now here what we did is we took 6 to the other side and there will be 0 on the place of 6 and now you can find the value of a , b , c ]

ii) 2x = -5y

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