Respuesta :
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's solve ~
Question - 1 :
[tex]\qquad \sf \dashrightarrow \: - 2x + 3y = 6[/tex]
[tex]\qquad \sf \dashrightarrow \: - 2x + 3y - 6[/tex]
[tex]\qquad \sf \dashrightarrow \: (- 2)x + (3)y + (- 6)[/tex]
comparing it to general equation, we get :
- [tex] \sf\dashrightarrow \: a = - 2[/tex]
- [tex] \sf\dashrightarrow \: b = 3[/tex]
- [tex] \sf\dashrightarrow \: c= - 6[/tex]
Similarly,
Question - 2 :
[tex]\qquad \sf \dashrightarrow \: 2x = - 5y[/tex]
[tex]\qquad \sf \dashrightarrow \: 2x + 5y = 0[/tex]
[tex]\qquad \sf \dashrightarrow \: (2)x + (5)y + 0 = 0[/tex]
comparing it with general equation, we get :
- [tex] \sf\dashrightarrow \: a = 2[/tex]
- [tex] \sf\dashrightarrow \: b = 5[/tex]
- [tex] \sf\dashrightarrow \: c = 0[/tex]
Step-by-step explanation:
i) -2x + 3y = 6
-2x + 3y +(-6) = 0
-2x + 3y - 6 = 0
Comparing this equation with ax + by + c = 0
- a = -2
- b = 3
- c = 6
[ Now here what we did is we took 6 to the other side and there will be 0 on the place of 6 and now you can find the value of a , b , c ]
ii) 2x = -5y