If a, b and c are integers then the correction option in the above case is that both equation 1 and 2 are correct.
What is the proves?
Note that:
- If a|(bc), then a|b is true
- If ab|bc, then b|c is true
Because:
Suppose one say a|b. Then one can see that an integer do exist which is n such that b = an.
Hence:
bc = (an)c = a(nc), so a|(bc) (the reverse is still the case or still applies)
Therefore, If a, b and c are integers then the correction option in the above case is that both equation 1 and 2 are correct.
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