Answer:
[tex]\huge\boxed{\sf Arc \ length = 6.11 \ ft.}[/tex]
Step-by-step explanation:
Theta = θ = 35°
Radius = r = 10 ft.
Arc length = ?
[tex]\displaystyle Arc \ length = 2 \pi r(\frac{\theta}{360} )[/tex]
Put the givens in the above formula
[tex]\displaystyle Arc \ length = 2 (3.14)(10)(\frac{35}{360} )\\\\Arc \ length = 2(3.14)(10)(0.097)\\\\Arc \ length = 6.11 \ ft.\\\\\rule[225]{225}{2}[/tex]