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Question 2
Consider a right angled triangle where one of the non-hypotenuse sides has
length 3 and the angle it makes with the hypotenuse is 65. What is the area of
this triangle?
A: 3cos65/2 B: 9tan65/2 C: 9sin65/2 D: 9cos65/2 E: 3sin65/2

Respuesta :

Using relations in a right triangle, the area of the triangle is given by:

B. 9tan(65º)/2.

What are the relations in a right triangle?

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
  • The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

In this problem, we have one leg(length 3) and the angle with the hypotenuse(65º), hence the other leg can be found as follows:

[tex]\tan{65^\circ} = \frac{x}{3}[/tex]

x = 3tan(65º).

What is the area of a right triangle?

The area of a right triangle is half the multiplication of it's legs, hence in this problem:

A = 1/2 x 3 x 3tan(65º) = 9tan(65º)/2.

Which means that option B is correct.

More can be learned about relations in a right triangle at https://brainly.com/question/26396675

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