36. Dennis set off from Town A at 10 A.M., driving at an average rate of speed of 52 mph. He reached
Town B at 2 PM. If William set off 1 hour 25 minutes earlier than Dennis and took the same route
at an average rate of speed of 40 mph., at what time would William reach Town B?

Respuesta :

The time William would arrive in town B IS 1 : 47 pm.

What time will William arrive in town B?

The first step is to determine the distance and the time of Dennis's travel.

Time = 14 hours (2 pm + 12) - 10 hours = 4 hours

Distance = time x average speed

4 x 52 = 208 miles

The second step is to determine the time of William's travel:

Distance / average speed = time

208 / 40 = 5.20 = 5 hours 12 minutes

Time William left for the trip = 10 am - 1 hour 25 minutes = 8 :35am

Time he would reach town B = 8 : 35am + 5 hours 12 minutes = 13 hours 47 minutes = 1 : 47 pm

To learn more about average speed, please check: https://brainly.com/question/21734785

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