How many grams of N2 gas are present in a 20.0 L tank of N2 that is at 290 K and 2.75 atm?

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.
V is the volume that occupies.
T is its temperature.
R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
n is the number of moles of the gas.

Mass of N₂

In this case, you know:

P= 2.75 atm
V= 20 L
T= 290 K
R= 0.082 [tex]\frac{atmL}{molK}[/tex]
n= ?

Replacing in the ideal gas law:

2.75 atm× 20 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 290 K

Solving:

n= (2.75 atm× 20 L)÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 290 K)

n= 2.31 moles

Being the molar mass of N₂ 28 g/mol, then the mass of 2.31 moles is calculated as:

mass= 28 [tex]\frac{g}{mole}[/tex]× 2.31 moles

Solving:

mass= 64.68 grams

Finally, 64.68 grams of N₂ gas are present in a 20.0 L tank of N₂ that is at 290 K and 2.75 atm.

Learn more about the ideal gas law:

https://brainly.com/question/4147359

#SPJ1