Answer:
[tex]-\dfrac{q}{p}[/tex]
Step-by-step explanation:
Slope-intercept form of a Linear Equation:
[tex]y = mx + b[/tex]
where:
- m is the slope
- b is the y-intercept
If line m has a y-intercept of c and a slope of p/q, then:
[tex]\textsf{Equation of line m}: \quad y = \dfrac{p}{q}x + c[/tex]
If two lines are perpendicular to each other, the product of their slopes will be -1.
Let a = slope of the line perpendicular to line m.
[tex]\implies a \times \dfrac{p}{q}=-1[/tex]
[tex]\implies a=-\dfrac{q}{p}[/tex]
Therefore, the slope of the a line that is perpendicular to line m is:
[tex]-\dfrac{q}{p}[/tex]
