Helpppp!!! The question says “which pair of linear equations described the graph of two perpendicular lines?” The options are

A. Y-2=3(x+1)
Y+4=1/3(x-5)

B. Y-2=3(x+1)
Y+4=3(x-5)

C. Y-2=3(x+1)
Y+4=-1/3(x-5)

D. Y-2=3(x+1)
Y+4=-3(x-5)

Perpendicular lines have a reciprocal slope to each other. So you find the answer by taking one of the slopes and flipping the fraction and switching the sign of it. In this example, the first equation has a slope of 3/1, so to be perpendicular the other equation needs a slope of -⅓.

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Helpppp!!! The question says “which pair of linear equations described the graph of two perpendicular lines?” The options are A. Y-2=3(x+1) Y+4=1/3(x-5) B. Y-2=3(x+1) Y+4=3(x-5) C. Y-2=3(x+1) Y+4=-1/3(x-5) D. Y-2=3(x+1) Y+4=-3(x-5)

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Helpppp!!! The question says “which pair of linear equations described the graph of two perpendicular lines?” The options are

A. Y-2=3(x+1)
Y+4=1/3(x-5)

B. Y-2=3(x+1)
Y+4=3(x-5)

C. Y-2=3(x+1)
Y+4=-1/3(x-5)

D. Y-2=3(x+1)
Y+4=-3(x-5)