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What is the period, in seconds, of a simple pendulum of length 5 meters? Use
the gravitational constant g = 9.8 m/s2 and round your answer to two decimal
places.

Respuesta :

[tex]T=2\pi \sqrt{(\frac{l}{g} )} \\T=2\pi \sqrt{\frac{5m}{(9.8m/s^{2}) } } \\[/tex]

[tex]T[/tex] ≈ [tex]4,49s[/tex]

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