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An artist creates a​ cone-shaped sculpture for an art exhibit. If the sculpture is 8 feet tall and has a base with a circumference of 23.236 ​feet, what is the volume of the​ sculpture? Use 3.14 for pi .

Respuesta :

Space

Answer:

The volume of the cone-shaped sculpture is equal to 114.631 ft³.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Geometry

Circumference Formula:
[tex]\displaystyle C = 2 \pi r[/tex]

  • r is radius

Volume Formula [Cone]:
[tex]\displaystyle V = \frac{\pi r^2 h}{3}[/tex]

  • r is radius
  • h is height

Step-by-step explanation:

Step 1: Define

Identify given.

h = 8 ft

C = 23.236 ft

Step 2: Find Radius r

  1. [Circumference Formula] Substitute in variables:
    [tex]\displaystyle \begin{aligned}C = 2 \pi r & \rightarrow 23.236 \ \text{ft} = 2(3.14)r \\\end{aligned}[/tex]
  2. Solve [Equality Properties]:
    [tex]\displaystyle \begin{aligned}C = 2 \pi r & \rightarrow 23.236 \ \text{ft} = 2(3.14)r \\& \rightarrow r = 3.7 \ \text{ft} \\\end{aligned}[/tex]

Step 3: Find Volume

  1. [Volume Formula - Cone] Substitute in variables:
    [tex]\displaystyle \begin{aligned}V = \frac{\pi r^2 h}{3} & \rightarrow V = \frac{(3.14)(3.7 \ \text{ft})^2(8 \ \text{ft})}{3} \\\end{aligned}[/tex]
  2. Evaluate:
    [tex]\displaystyle \begin{aligned}V = \frac{\pi r^2 h}{3} & \rightarrow V = \frac{(3.14)(3.7 \ \text{ft})^2(8 \ \text{ft})}{3} \\& \rightarrow V = \boxed{ 114.631 \ \text{ft}^3 } \\\end{aligned}[/tex]

∴ the volume of the artist-created sculpture is 114.631 ft³.

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Learn more about Geometry: https://brainly.com/question/27732359

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Topic: Geometry

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