Answer:
The required mass would be 198.15g
Explanation:
No of moles = mass ÷ molar mass
No of moles = concentration × volume
concentration = 6M
Molar mass= 132.1 grams/mole
Volume = 250mL= 0.25L
No of moles = 6 × 0.25 = 1. 5 moles
Mass = no of moles × Molar mass
Mass = 1.5 × 132.1
Mass = 198. 15g
The required mass is 198.15g
