The perimeter and area of the original are 20 ft and 23.5 square ft and the enlarged figure are50 ft and 146.875 square ft.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
The figure is the combination of a triangle and a square.
The area of the original (A₀) figure will be
[tex]\rm A_o = \dfrac{1}{2} \times 3 \times 5 + 4 \times 4\\\\A_o = 23.5 \ ft^2[/tex]
The perimeter of the original figure (P₀) will be
[tex]\rm P_o = 3 + 5 + 4 + 4 + 4\\\\P_o = 20 \ ft[/tex]
The scale factor is 2.5.
Then the dimension of the triangle will be
h = 2.5 × 3 = 7.5 ft
b = 2.5 × 5 = 12.5 ft
Then the dimension of the square will be
a = 2.5 × 4
a = 10 ft
The area of the new figure will be
[tex]\rm A = \dfrac{1}{2} \times 7.5\times 12.5 + 10*10\\\\ A = 146.875 \ ft^2[/tex]
The perimeter of the new figure will be
[tex]\rm P= 7.5 + 12.5 + 10+ 10+ 10\\\\P = 50 \ ft[/tex]
More about the geometry link is given below.
https://brainly.com/question/7558603
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Answer:
To find the perimeter of an enlarged figure, you can multiply the original figure’s perimeter by the scale factor. You could also multiply each dimension of the original figure by the scale factor to find the dimensions of the enlarged figure, and then add to find the perimeter.
