The axis of symmetry of the quadratic equation is [tex]x = \sqrt 6[/tex]
How to express the solution?
One of the root is given as:
[tex]x = -2 - \sqrt 6[/tex]
As a general rule, the solution to a quadratic equation is represented by:
[tex]x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]
This means that the actual root of the given root is:
[tex]x = -2 \pm \sqrt 6[/tex]
So, the other root is:
[tex]x = -2 + \sqrt 6[/tex]
Subtract both roots and divide it by 2 to determine the axis of symmetry
[tex]x = \frac{|-2 - \sqrt 6 + 2 - \sqrt 6|}{2}[/tex]
Evaluate
[tex]x = \frac{|-2\sqrt 6|}{2}[/tex]
Remove the absolute sign
[tex]x = \frac{2\sqrt 6}{2}[/tex]
Divide
[tex]x = \sqrt 6[/tex]
Hence, the axis of symmetry of the equation is [tex]x = \sqrt 6[/tex]
Read more about quadratic equations at:
https://brainly.com/question/8649555
#SPJ1
