Seudónimo Seudónimo
  • 20-04-2022
  • Chemistry
contestada

help please acids and basis

help please acids and basis class=

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Аноним Аноним
  • 21-04-2022

Let's see

  • [OH-] be x

[tex]\\ \rm\Rrightarrow pOH=-log[OH-][/tex]

[tex]\\ \rm\Rrightarrow pOH=-logx[/tex]

[tex]\\ \rm\Rrightarrow 4.86=-logx[/tex]

[tex]\\ \rm\Rrightarrow logx=-4.86[/tex]

[tex]\\ \rm\Rrightarrow x=10^{-4.86}[/tex]

[tex]\\ \rm\Rrightarrow x=1.38M[/tex]

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