Launching the fuse is an illustration of a quadratic model, and the equation of the quadratic model is f(x) = 15(x - 3)(x - 8)
How to model the quadratic equation?
From the complete question, the zeros of the quadratic function are:
x = 3 and x = 8
Rewrite as:
x - 3 = 0 and x - 8 = 0
So, the quadratic equation is:
f(x) = a(x - 3)(x - 8)
Also from the graph, we have the following point
(x,y) = (4,60)
Substitute 4 for x and 60 for f(x) in the function
a(4 - 3)(4 - 8) = 60
Evaluate the difference
a(1)(-4) = 60
Evaluate the product
-4a = 60
Divide both sides by 4
a = -15
Substitute a = -15 in f(x) = a(x - 3)(x - 8)
f(x) = -15(x - 3)(x - 8)
Hence, the equation of the quadratic model is f(x) = 15(x - 3)(x - 8)
Read more about quadratic models at:
https://brainly.com/question/8649555
