Given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.
Capacitance of a Capacitor
The capacitance of a capacitor is simply the ratio of the maximum charge that can be stored in a capacitor to the applied voltage across its plates.
It is expressed as;
C = Q / V
Where Q is charge and V is potential difference.
Given the data in the question;
- Capacitance C = 2.00 pF = 2.0 × 10⁻¹² F
- Potential difference V = 2.5V
- Amount of charge stored Q = ?
To determine the amount of charge stored, we substitute our given values into the expression above.
C = Q / V
Q = CV
Q = (2.0 × 10⁻¹² F) × 2.5V
Q = 5 × 10⁻¹²C
Q = 5pC
Therefore, given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.
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