Respuesta :
Answer:
0 < t ≤ 8 (in hours)
Up to (and including) 8 hours
Step-by-step explanation:
Let t = number of hours the room is rented
Given:
- Reservation fee = $39
- Fee per hour = $9.80
- Maximum total cost = $117.40
Create an equation using the given information and solve for t:
⇒ 39 + 9.8t ≤ 117.4
Subtract 39 from both sides:
⇒ 9.8t ≤ 78.4
Divide both sides by 9.8
⇒ t ≤ 8
Therefore, the possible amounts of time for which they could rent the meeting room is 0 < t ≤ 8 (in hours)
Answer:
8 is the very maximum number of hours the room can be rented. As long as 8 is not exceeded, the room is rentable for what money the math club has.
Step-by-step explanation:
Givens
- Maximum payment = 117.40
- Cost per hour = 9.80
- Fixed charge = 39 dollars
Formula
payment ≥ 39 + 9.80*t where t is in hours.
Solution
117.40 ≥ 39 + 9.80*t Subtract 39 from both sides.
117.40 - 39 ≥9.80*t
78.40 ≥ 9.80*t Divide by 9.8
78.40/9.80 ≥ 9.80*t/9.80
8 ≥ t
Answer t≥ 8