a. Jessica's has a greater linear speed.
b. The centripetal acceleration of Julie and her horse is 0.148 m/s².
Jessica's has a greater linear speed.
To answer the question, we need to know what Linear speed is.
This is the tangential speed at which an object in circular motion moves. It is given by v = rω where
Now, given that Jessica is riding on a merry-go-round on an outer horse that sits at a distance of 8.0 m from the center of the ride and Jessica's sister, Julie, is on an inner horse located 6.0 m from the ride's center. Also, the merry-go-round is moving at constant angular speed.
Since Linear speed v = rω and ω = constant,
So, v ∝ r.
So, the girl with the greater distance from the center of the merry-go-round would have the greater linear speed.
Since
Since
So, Jessica's has a greater linear speed.
The centripetal acceleration of Julie and her horse is 0.148 m/s².
Centripetal acceleration a = rω² where
Since the merry-go-round turns once every 40.0 s, we have that ω = 2π/40.0 s
= π/20.0 s
= 0.157 rad/s
Since a = rω²
Substituting the values of the variables into the equation, we have
a = rω²
a = 6.0 m × (0.157 rad/s)²
a = 6.0 m × 0.0247 rad²/s²
a = 0.148 m/s²
So, the centripetal acceleration of Julie and her horse is 0.148 m/s².
Learn more about linear speed here:
https://brainly.com/question/25653453
