The temperature of a 1.7379 mole of a gas with a pressure of 1.4948 atm and volume of 92.202 L is 965.69K .
How to calculate temperature?
The temperature of a given gas can be calculated using the ideal gas law equation:
PV = nRT
Where;
- P = pressure = 1.4948atm
- V = volume = 92.202L
- R = gas law constant = 0.0821 Latm/molK
- n = number of moles = 1.7379mol
- T = temperature
1.4948 × 92.202 = 1.7379 × 0.0821 × T
137.82 = 0.142T
T = 137.82 ÷ 0.142
T = 965.69K
Therefore, the temperature of a 1.7379 mole of a gas with a pressure of 1.4948 atm and volume of 92.202 L is 965.69K.
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