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each morning, danai buys breakfast on her why to work. In the past thirty days, she bought a bagel on 6 days, a banana on 12 days, a doughnut on 3 days, and an orange on 9 days. If she bought one item per day, what is the probability that she bought either a banana or an orange? Show or explain your work and write you answer in the space provided.

Respuesta :

mhanifa

Answer:

  • 0.7 or 70%

Step-by-step explanation:

Total number of days

  • 6 + 12 + 3 + 9 = 30

The number of days she bought a banana or orange

  • 12 + 9 = 21

The probability of buying a banana or an orange is

  • P(b or o) = 21/30 = 0.7 = 70%
semsee45

Answer:

[tex]\sf \dfrac{7}{10}=0.7=70\%[/tex]

Step-by-step explanation:

Given information:

  • Bagel bought on 6 days
  • Banana bought on 12 days
  • Doughnut bough on 3 days
  • Orange bought on 9 days

Total number of days = 30

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Probability of buying a banana:

[tex]\implies \sf P(Banana)=\dfrac{12}{30}[/tex]

Probability of buying an orange:

[tex]\implies \sf P(Orange)=\dfrac{9}{30}[/tex]

Therefore,

[tex]\implies \sf P(Banana) \: or \: P(Orange)=\sf \dfrac{12}{30}+\dfrac{9}{30}=\dfrac{21}{30}=\dfrac{7}{10}[/tex]

So the probability of buying either a banana or an orange is:

  [tex]\sf \dfrac{7}{10}=0.7=70\%[/tex]

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