72 g of Copper(i) oxide will be produced by 40 g of CuO base on the law of conservation of mass.
The law of conservation of mass states that mass remains constant at the end of every reaction.
The equation of the reaction is given below:
[tex]4CuO → 2Cu_2O + O_2[/tex]
Based on the equation of reaction, 4 moles of copper (ii) oxide produces 2 moles of copper (i) oxide.
Mass of 4 moles of CuO = 4 × 80 = 160 g
Mass of 2 moles of copper (i) oxide = 2 × 144 g = 288 g
Mass of Copper(i) oxide produced by 40 g of CuO will be: 40 × 288/160 = 72 g
Therefore, 72 g of Copper(i) oxide will be produced by 40 g of CuO.
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