Using conditional probability, it is found that there is a 0.521 = 52.1% probability that they have perfect attendance, given they made he honor roll.
Conditional probability is the probability of one event happening, considering a previous event. The formula is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which:
In this problem, the events are:
The probabilities are given by:
[tex]P(A) = 0.48, P(A \cap B) = 0.25[/tex]
Hence the conditional probability is given by:
[tex]P(B|A) = \frac{0.25}{0.48} = 0.521[/tex]
0.521 = 52.1% probability that they have perfect attendance, given they made he honor roll.
More can be learned about conditional probability at https://brainly.com/question/14398287
#SPJ1
