[tex] \large \red{\frak{ Question}}[/tex]
The sum of 3/4th of A’s salary and 5/3rd of B’s salary is ₹16,000. The difference of their salaries is ₹2000. If B’s salary is less than that of A, then what is the salary of B (in ₹)?
(a) 8000 (b) 2000
(c) 6000 (d) 12,000​
[tex] \pink{ \dag \: \large\sf{ With \: Explanation }}[/tex]
​[tex] \blue{ \dag \: \large\sf{No Spam }}[/tex]

Respuesta :

Ankit

Answer:

[tex] \sf \: \fbox{Option C) \: The salary of B is 6000₹}[/tex]

Step-by-step explanation:

Let the salary or A is x and salary of B is y.

now,

Condition one,The sum of 3/4th of A’s salary and 5/3rd of B’s salary is ₹16,000.

writing above statement in equation form,

[tex] \sf \frac{3x}{4} + \frac{5y}{3} = 16000[/tex]

Multiplying above equation with twelve,

[tex] \sf \frac{3x}{4} + \frac{5y}{3} = 16000 \\ \sf \frac{12 \times 3x}{4} + \frac{12 \times 5y}{3} = 16000 \times 12 \\ \sf \fbox{9x + 20y = 192000} \rightarrow eq. 1[/tex]

and condition two,

The difference of their salaries is ₹2000

[tex] \sf \: x - y = 2000[/tex]

Multiplying above equation with 20

[tex] \sf \fbox{\: 20x -20y = 40000} \rightarrow eq.2[/tex]

On adding equation 1 and equation 2,

[tex] \sf9x + \cancel{20y} = 192000 \\ \sf 20x - \cancel{20y} = 40000 \\ \hline \sf 29x + 0y = 232000 \\ \sf x = \frac{232000}{29} \\ \sf \: \fbox{x = 8000₹}[/tex]

Substituting the value of x in,

[tex] \sf \: x - y = 2000 \\ \sf \: 8000 - y = 2000 \\ \sf \: y = 8000 - 2000 \\ \sf \fbox{y = 6000₹}[/tex]

[tex] \sf \: \fbox{The salary of B is 6000₹}[/tex]

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