The resistance of the electric space heater dissipating the given amount of power is 10.9Ω.
Ohm's law states that "the voltage across the cross-section of a conductor is directly proportional to the current passing through it.
It is expressed as;
V = I × R
Where V is voltage, I is current and R is resistance.
Also, electrical power is the product of current and voltage.
P = I × V meaning I = P/V
Hence,
V = (P/V) × R
R = V² / P
Given the data in the question;
To determine the resistance of the heater, we substitute our given values into the derived expression above.
R = V² / P
R = (120V)² / 1320W
R = 14400V² / 1320W
R = 10.9Ω
Therefore, the resistance of the electric space heater dissipating the given amount of power is 10.9Ω.
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