Considering a quadratic equation, it is found that:
Considering the height in feet, it is given by:
h(t) = -4.9t² + v(0)t + h(0)
In which:
In this problem, we have that h(0) = 6, v(0) = 16, hence the equation is given by:
h(t) = -4.9t² + 16t + 6
Which is a quadratic equation with coefficients a = -4.9, b = 16, c = 6. Hence the maximum height is found as follows:
[tex]\Delta = b^2 - 4ac = 16^2 - 4(-4.9)(6) = 373.6[/tex]
[tex]h_{MAX} = -\frac{\Delta}{4a} = -\frac{373.6}{-4(4.9)} = 19.06[/tex]
The maximum height of the volleyball is of 19.06 feet.
It hits the ground at the roots, hence:
The solutions are:
[tex]x_1 = \frac{-16 + \sqrt{373.6}}{-9.8} = -0.34[/tex]
[tex]x_2 = \frac{-16 - \sqrt{373.6}}{-9.8} = 3.6[/tex]
Time is a positive measure, hence:
The volleyball will hit the ground after 3.6 seconds.
More can be learned about quadratic equations at https://brainly.com/question/24737967
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