Claire invested $2,300 in an account paying an interest rate of
6
1
4
6
4
1

% compounded annually. Henry invested $2,300 in an account paying an interest rate of
6
3
4
6
4
3

% compounded monthly. To the nearest dollar, how much money would Claire have in her account when Henry's money has tripled in value?

Respuesta :

Using compound interest, it is found that Claire will have $6,186 in her account when Henry's money has tripled in value.

What is compound interest?

The amount of money earned, in compound interest, after t years, is given by:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

In which:

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal value).
  • n is the number of times that interest is compounded per year.

For Henry, we have that r = 0.0675, n = 12. The time it takes for the amount to triple is t when A(t) = 3P, hence:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

[tex]3P = P\left(1 + \frac{0.0675}{12}\right)^{12t}[/tex]

[tex](1.005625)^{12t} = 3[/tex]

[tex]\log{(1.005625)^{12t}} = \log{3}[/tex]

[tex]12t\log{(1.005625)} = \log{3}[/tex]

[tex]t = \frac{\log{3}}{12\log{(1.005625)}}[/tex]

t = 16.32.

Then, for Claire, we have that the parameters are as follows:

P = 2300, r = 0.0625, n = 1, t = 16.32.

Hence, the amount is given by:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

[tex]A(t) = 2300\left(1 + \frac{0.0625}{1}\right)^{16.32}[/tex]

A(t) = 6186.

Claire will have $6,186 in her account when Henry's money has tripled in value.

More can be learned about compound interest at https://brainly.com/question/25781328

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