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The cylinder of a car's engine has a volume of 0.6250 L when the piston is at the bottom of the cylinder. When the piston is at the top of the cylinder the volume is 0.0600 L. If the cylinder is filled with air at an atmospheric pressure of 765.1 mm Hg the piston is at the bottom, what is the pressure in units of kPa when the piston is at the top of the cylinder?

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The new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa

Boyle's law

Boyle's law states that "volume of a given quantity of gas is inversely proportional to its pressure  as long as temperature remains constant.

It is expressed as;

P₁V₁ = P₂V₂

Given the data in the question;

  • Initial volume V₁ = 0.6250L
  • New volume V₂ = 0.0600L
  • Initial pressure P₁ = 765.1mmHg = 1.0067107atm
  • New pressure P₂ = ?

To determine the new pressure as the piston is at the top of the cylinder, we substitute our given values into the expression above.

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.0067107atm × 0.6250L ) / 0.0600L

P₂ = 0.629194188Latm / 0.0600L

P₂ = 10.4865698atm

P₂ = 1062.55kPa

Therefore, the new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa

Learn more about Boyle's law here: brainly.com/question/1437490

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