Answer:
Below!
Step-by-step explanation:
Let the irrational number be known as "x".
[tex]\implies -\sqrt{41} \times x = 1[/tex]
Divide both sides by -√41.
[tex]\implies \dfrac{(-\sqrt{41} \times x)}{-\sqrt{41} } = \dfrac{1}{\sqrt{-41} }[/tex]
[tex]\implies x = \dfrac{1}{-\sqrt{41} }[/tex]
Take the "-" to the numerator:
[tex]\implies x = \dfrac{-1}{\sqrt{41} }[/tex]
Use parenthesis to isolate the "-"
[tex]\implies x = -\huge\text{(}\dfrac{1}{\sqrt{41} } \huge\text{)}[/tex]
Note: 1 can also be written as √1. (√1 = √1 × √1 = 1)
[tex]\implies {x = -\huge\text{(}\dfrac{\sqrt{1}}{\sqrt{41} }\huge\text{)}}[/tex]
Combine the roots in the equation:
[tex]\implies {x = -\huge\text{(}\sqrt{\dfrac{1}{41} }} \huge\text{)}}[/tex]
Remove the parenthesis:
[tex]\implies {x = -\sqrt{\dfrac{1}{41} }}[/tex]
Thus, Option C is correct.
