contestada

Two bags, A and B, each contain only green marbles and red marbles.
There are 6 green marbles and 4 red marbles in bag A.
There are 8 green marbles and 2 red marbles in bag B.
One marble is going to be taken at random from bag A and placed in bag B.
A marble is then going to be taken at random from bag B.
Work out the probability that this marble will be a green marble. ​

Respuesta :

Using it's concept, it is found that there is a 0.7818 = 78.18% probability that this marble will be a green marble. ​

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

There are two ways to end up with a green marble selected.

  • Green in bag A(6/10 probability) and in bag B(9/11 probability).
  • Red in bag A(4/10 probability) and green in bag B(8/11 probability).

Hence, the probability that this marble will be a green marble is given by:

[tex]p = \frac{6}{10} \times \frac{9}{11} + \frac{4}{10} \times \frac{8}{11} = \frac{54 + 32}{110} = 0.7818 = 78.18\%[/tex]

More can be learned about probabilities at https://brainly.com/question/14398287

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas