It took Fred 12 hours to travel over pack ice from one town in the arctic to another town 360 miles away. During the return journey, it took him 15 hours. Assume the pack ice was drifting at a constant rate, and that Fred’s snowmobile was traveling at a constant speed relative to the pack ice. What was the speed of Fred’s snowmobile?

It took Fred 12 hours to travel over pack ice from one town in the arctic to another town 360 miles away During the return journey it took him 15 hours Assume t class=

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Using the relation between velocity, distance and time, it is found that the speed of Fred’s snowmobile was of 27 miles per hour.

What is the relation between velocity, distance and time?


Velocity is distance divided by time, hence:

[tex]v = \frac{d}{t}[/tex]

It took Fred 12 hours to travel over pack ice from one town in the arctic to another town 360 miles away, when the ice was drifting in the same direction, hence:

[tex]v_i + v_s = \frac{360}{12}[/tex]

[tex]v_i + v_s = 30[/tex]

[tex]v_i = 30 - v_s[/tex]

In the return trip, with the ice in opposite direction he took 15 hours, hence:

[tex]v_s - v_i = \frac{360}{15}[/tex]

[tex]v_s - v_i = 24[/tex]

Since [tex]v_i = 30 - v_s[/tex]:

[tex]v_s - 30 + v_s = 24[/tex]

[tex]2v_s = 54[/tex]

[tex]v_s = 27[/tex]

The speed of Fred’s snowmobile was of 27 miles per hour.

More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569

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