For the given arithmetic sequence we have:
We know that we have 20 seats on the front row, and then we add 3 more on each row, so the formula will be:
[tex]A_n = 20 + (n - 1)*3[/tex]
This gives the number of seats on the n-th row.
B) The last row has 83 seats, then we need to solve:
[tex]A_n = 20 + (n - 1)*3 = 83\\\\(n - 1)*3 = 83 - 20 = 63\\\\n - 1 = 63/3 = 21\\\\n = 21 + 1 = 22[/tex]
So we conclude that there are 22 rows.
C) The total number of seats will be:
[tex]\sum_{n = 1\ to\ 22} (20 + (n - 1)*3)[/tex]
D) Instead of using the sum above (we should add 22 terms) we use the general formula for the sum of N terms in an arithmetic sequence:
[tex]S_N = (N/2)*(2A_1 + (N - 1)*d)[/tex]
In this case, we replace N by 22, and d is the common difference of the sequence, which we know is equal to 3, so we wil have:
[tex]S_{22} = (22/2)*(2*20+ (22 - 1)*3) = 11*(40 + 21*3) = 1,133[/tex]
There are 1,133 seats in total.
If you want to learn more about sequences, you can read:
https://brainly.com/question/7882626