The molarity of the solution that contains 87.75 g of NaCl in 500 mL of the solution is 3 M
This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
Mole = mass / molar mass
Mole of NaCl = 87.75 / 58.5
Mole of NaCl = 1.5 mole
Molarity = mole / Volume
Molarity = 1.5 / 0.5
Molarity = 3 M
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