[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ C(\stackrel{x_1}{1}~,~\stackrel{y_1}{0})\qquad D(\stackrel{x_2}{-7}~,~\stackrel{y_2}{2}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ -7 + 1}{2}~~~ ,~~~ \cfrac{ 2 + 0}{2} \right)\implies \left(\cfrac{-6}{2}~~,~~\cfrac{2}{2} \right)\implies (-3~~,~~1)[/tex]
Answer:
Midpoint: (-0.5, -1)
Step-by-step explanation:
Solution: M=([tex]x m[/tex],[tex]ym[/tex])/2 or ([tex]x[/tex]+[tex]x[/tex]/2, [tex]y[/tex]+[tex]y[/tex]/2)
add the first [tex]x[/tex] coordinate plus the second [tex]x[/tex] coordinate
do the same for the two [tex]y[/tex] coordinates
then divide them both by 2
should look something like this: (1+0 /2, -7+2 /2)
[tex]x[/tex]= 1+0= 1 / 2 + 0.5 or one half 1/2
[tex]y[/tex]= -7+2= -5 / 2 = -2.5 or four one half -2 1/2
BUT we are not done here, since we cant divide 1/2 no more because it will still give us the same answer (0.5) we move into the next number, -2 1/2, -2 x 1/2 = -1
So our answer is (-0.5, -1)
hoped it helped! <3
