Answer:
Step-by-step explanation:
Given the equation: y = 8 * 2ˣ, substitute the x-values in the table for x in your equation, to find the y-values.
For x = -1
[tex]y = 8 * 2^x\\y=8*2^{-3}\\y=8*\frac{1}{2^3} < ==negative\ exponent\ property: x^{-n}=\frac{1}{x^n}\\y=8*\frac{1}{8}\\y=8*0.125\\y=1\\\\(-1,1)[/tex]
For -2:
[tex]y = 8 * 2^x\\y=8*2^{-2}\\y=8*\frac{1}{2^2} < ==negative\ exponent\ property: x^{-n}=\frac{1}{x^n}\\y=8*\frac{1}{4}\\y=8*0.25\\y=2\\\\(-2,2)[/tex]
For -1:
[tex]y = 8 * 2^x\\y=8*2^{-1}\\y=8*\frac{1}{2^1} < ==negative\ exponent\ property: x^{-n}=\frac{1}{x^n}\\y=8*\frac{1}{2}\\y=8*0.5\\y=4\\\\(-1,4)[/tex]
For 0:
[tex]y = 8 * 2^x\\y=8*2^0\\y=8*\frac{1}{2^2} < ==zero\ exponent\ property: x^0=1\\y=8*1\\y=8\\\\(0,8)[/tex]
For 1:
[tex]y = 8 * 2^x\\y=8*2^1\\y=8*2\\y=16\\\\(1,16)[/tex]
For 2:
[tex]y = 8 * 2^x\\y=8*2^2\\y=8*4\\y=32\\\\(2,32)[/tex]
For 3:
[tex]y = 8 * 2^x\\y=8*2^3\\y=8*8\\y=64\\\\(3,64)[/tex]
Hope this helps!
