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There are 8 red marbles, 2 green marbles, and 5 blue marbles in a bag. Marbles are replaced after each draw. What is the probability that the first marble drawn is red and the second marble drawn is green?

Respuesta :

Answer:

[tex]\frac{16}{225}[/tex]

Step-by-step explanation:

When attempting probability problems we want to figure out the chances of something happening. This turns into something like:

[tex]\frac{\text{marble drawn}}{\text{total marbles}}[/tex]

In this case we have 8 red marbles, 2 green marbles, and 5 blue marbles in a bag. That brings us to a total of 15 marble.

Since we want to first draw a red marble the chance of that happening would be:

[tex]\frac{8\text{(the marble drawn)}}{15\text{(total # of marbles)}}[/tex]
Now we replace the marble as stated in the problem so we then draw the next marble, which is green.

[tex]\frac{2\text{(the marble drawn)}}{15\text{(total number of marbles)}}[/tex]

All that's left is to multipy the values we got:

[tex]\frac{8}{15} *\frac{2}{15}=\frac{16}{225}[/tex]

That's our answer.

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