Respuesta :
Answer:
[tex]\sf factorisation\hookrightarrow \: (x- 4)(x - 5)[/tex]
Step-by-step explanation:
Given equation
[tex] \sf {x}^{2} - 9x + 20 [/tex]
Rules for factorisation,
distribute the middle term in such a way that constant of each term when multiplied outputs the last number.
The middle term -9x can be written as sum of -5x and -4x, and when we multiply -5 with -4 it turns+20.
rewriting equation,
[tex] \sf \hookrightarrow {x}^{2} - 5x - 4x + 20 \\ \sf \hookrightarrow x(x - 5) - 4(x - 5) \\ \sf \hookrightarrow \: (x- 4)(x - 5)[/tex]
[tex] \sf factorisation\hookrightarrow \: (x- 4)(x - 5)[/tex]
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Answer:
- (x - 5)(x - 4)
[tex] \: [/tex]
Step-by-step explanation:
So, here we have to factorise the polynomial :
[tex]\\ \longrightarrow \sf \qquad {x}^{2} - 9x + 20\\ \\[/tex]
We are to find two numbers such that,
[tex]\\ {\longrightarrow \pmb{\sf {\qquad p + q = 9 \:}}} \\ \\[/tex]
[tex]\\ {\longrightarrow \pmb{\sf {\qquad p \times q = 20 \:}}} \\ \\[/tex]
The two numbers are 4 and 5, so
[tex]\\ \longrightarrow \sf \qquad {x}^{2} - 5x - 4x+ 20\\ \\[/tex]
Finding common factors :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad {x} (x - 5) - 4(x - 5) \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad (x - 5) (x - 4) \:}}} \\ \\[/tex]
Some points to know :
- Factorisation is the reverse process of multiplucation.
- The Factorisation is the process of finding two or more expressions such that their product is the given expression