Step-by-step explanation:
1)
[tex] \sin(theta) = \frac{opposite \: side}{hypotenuse} [/tex]
[tex] \sin(30) = \frac{x}{10} = \frac{1}{2} [/tex]
[tex] \frac{x }{1} = \frac{10}{2} [/tex]
[tex]x = 5[/tex]
In right Angles traingle
By using Pythagoras theorm
we get
x²+y²=10²
25+y²=100
y²=75
y=5√3
x=5,y=5√3
2)
Area of equilateral traingle =
[tex] \frac{ \sqrt{3} }{4} {a}^{2} [/tex]
required area
[tex] \frac{ \sqrt{3} }{4} \times {6}^{2} [/tex]
[tex] \frac{36 \sqrt{3} }{4} [/tex]
[tex]9 \sqrt{3} [/tex]
