Respuesta :
Answer:
See below ↓↓
Step-by-step explanation:
- Height of ladder = 20 feet
- Distance of base of ladder from house = 3 feet
- Angle must not be < 70°
Taking the cos ratio of the angle
- Let the angle formed be α
- cos α = adjacent side / hypotenuse
- cos α = 3 / 20 = 0.15
- α = cos⁻¹ (0.15)
- α = 81.37°
⇒ The angle formed is safe
Finding furthest possible distance
- Take α to be 70°
- cos 70° = 0.34 = x/20
- ⇒ x = 20 x 0.34 = 6.8 feet
Answer:
Yes, the angle formed between the ground and the ladder is safe
6.84 ft (nearest hundredth)
Step-by-step explanation:
We can use the cos trig ratio to determine the angle made between the 20ft ladder and 3ft from the base of the house (see first attached image for sketch).
[tex]\sf \cos(\theta)=\dfrac{A}{H}[/tex]
where:
- [tex]\theta[/tex] is the angle
- A is the side adjacent to the angle
- H is the hypotenuse
Given:
- A = 3 ft
- H = 20 ft
[tex]\sf \implies \cos(\theta)=\dfrac{3}{20}[/tex]
[tex]\sf \implies \theta=\cos^{-1}\left(\dfrac{3}{20}\right)[/tex]
[tex]\sf \implies \theta=81.37307344..^{\circ}[/tex]
Therefore, as the ladder is forming an 81.37° angle and 81.37...° > 70° the angle formed between the ground and the ladder is safe.
To find the furthest possible distance the ladder can be placed, set [tex]\theta[/tex] to 70° (max safe angle) and the hypotenuse (ladder length) to 20, then solve for A (see second attache image for sketch):
[tex]\sf \implies \cos(70^{\circ})=\dfrac{A}{20}[/tex]
[tex]\sf \implies A=20\cos(70^{\circ})[/tex]
[tex]\sf \implies A=6.840402867...\: \sf ft[/tex]
So the furthest possible distance the ladder can be placed to maintain a safe angle is 6.84 ft (nearest hundredth).

