Answer:
x = -9
Step-by-step explanation:
find x for -3 + x = 2 (x+3)
-3 + x = 2 (x + 3) <== distribute
-3 + x = 2x + 6 <== subtract 1x from both sides
-x -x
-3 = x + 6 <== subtract 6 from both sides
-6 -6
-9 = x or x = -9
Hope this helps!
Given Equation :
[tex]{\longrightarrow \pmb{\sf {\qquad - \: 3+x=2(x+3)}}} \\ \\[/tex]
Solution :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad - \: 3+x=2(x+3)}}} \\ \\[/tex]
Using Distributive property for the right side we get :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad - \: 3+x=2x+ 6 }}} \\ \\[/tex]
Now, subtracting 2x from both sides we get :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad - \: 3+x - 2x =2x - 2x + 6 }}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad - \: 3- x = 6 }}} \\ \\[/tex]
Now, Adding 3 to both sides we get :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad - \: 3 + 3- x = 6 + 3 }}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad- \: x = 9 }}} \\ \\[/tex]
Now, Multiplying both sides by (-1) we get :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad (- 1)(- x) = ( - 1)9 }}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad x = - 6 }}} \\ \\[/tex]
Therefore,
