There are 32 different combinations that she can select out of the 5 pedals.
We want to get the total number of different combinations that we can make with 5 different pedals.
Remember that for a set of N elements, the number of different sets of K elements that we can make is:
[tex]C(N, K)=\frac{N!}{(N - K)!*K!}[/tex]
In this case, the total number of different combinations that we can make with the 5 pedals is given by:
C = C(5, 0) + C(5, 1) + C(5, 2) + C(5, 3) + C(5, 4) + C(5, 5).
Let's calculate each one of these:
[tex]C(5, 0) = \frac{5!}{(5 - 0)!*0!} = \frac{5!}{5!} = 1\\\\C(5, 1) = \frac{5!}{(5 - 1)!*1!} = \frac{5!}{4!} = 5\\\\C(5, 2) = \frac{5!}{(5 - 2)!*2!} = \frac{5!}{3!*2!} = \frac{5*4}{2} = 10\\\\C(5, 3)= \frac{5!}{(5 - 3)!*3!} = \frac{5!}{3!*2!} = \frac{5*4}{2} = 10\\\\\\C(5, 4) = \frac{5!}{(5 - 4)!*4!} = \frac{5!}{4!} = 5\\\\C(5, 5) = \frac{5!}{(5 - 5)!*5!} = 1[/tex]
So the total number of different combinations is:
C = 1 + 5 + 10 + 10 + 5 + 1 = 32
If you want to learn more about combinations, you can read:
https://brainly.com/question/11732255
