A cube of Iron, 0.0800 m on a side, has a density of 7874 kg/m^3. What is its mass? a (Unit = kg)

The mass of the iron cube of side 0.0800 m, having a density of 7874 kg/m³ is 50.39 kg.
Mass can be defined as the quantity of matter a body contains
To calculate the mass of the iron cube, we use the formula below.
Formula:
Where:
From the question,
Given:
Substitute these values into equation 1
Hence, The mass of the iron cube is 50.39 kg.
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