Hello !
Your answer will be is :
No, [tex]3^4^x^-^5[/tex] is higher then 8.
Let's go with step-by-step explanation ~
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[tex]\huge \red {\fbox {\mathbb{Explanation :}}}[/tex]
[tex]\sf{3^4^x^-^5}[/tex]
[tex]\sf{\frac{3^4^x}{3^5}[/tex]
[tex]\sf{\frac{3^4^x}{243}[/tex]
Hopefully this helps you !
#LearnWithBrainly
[tex]\underline{Answer :}[/tex]
Dollixna ~
[tex]Hello[/tex] [tex]There![/tex]
I'll will be helping your question today!
Let's do this step-by-step explanantion!
[tex]3^4^x^-^5 < 8[/tex]
Apply exponent rules:
[tex]4x-5 < 3log3(2)[/tex]
[tex]4x-5 < 31log3(2): x < \frac{3log3(2)+5}{4}[/tex]
Answer:
[tex]< \frac{3log3(2)+5}{4}[/tex]
[tex]\frac{3log3(2+5)}{4}[/tex]
[tex]2+5=7[/tex]
[tex]=\frac{3log3(7)}{4}[/tex]
Answer:
[tex]\frac{3log3(7)}{4}[/tex]
Answer could be: [tex]< \frac{3log3(2)+5}{4} or\frac{3log3(7)}{4}[/tex]
Hopefully, this helps you!!
#LearnWithBrainlyAlways~
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