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A basketball player is standing on the floor from the basket as in Figure Assuming that the height of the basket and player are of the same height. He shoots the ball at angle 45 o with the horizontal. The height covered through the trajectory is 2.05 m 0 = 45° O ji 18°C Clear ло ENG US 19​

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okpalawalter8

The ball will operate under the laws of parabolic projectile motion and possess features sure as

The acceleration of the basketball at the highest point in its trajectory is a=0

What is are the characteristics of the throw?

Question Parameters:

the basket and player are of the same height.

He shoots the ball at angle 45 o

The height covered through the trajectory is 2.05 m 0 = 45°

The ball will create a parabolic shape to make a basket

Generally, the equation for the projectile motion is mathematically given as

y = (tan θ0)x – gx2/2(v0cosθ0)2

Therefore

This formula will calculate the motion of the ball.

With the y as its vertical representation and x as its horizontal representation

In conclusion, characteristics of the throw

  • The acceleration of the basketball at the highest point in its trajectory is

a=0

  • The height of the ball is given as h =Usin\theta

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