Answer:
d) A ball is thrown directly upward from an initial height of 7 feet, will reach a maximum height of 19.3 ft in 0.9 s, and finally will hit the ground in 2 s.
Step-by-step explanation:
The y-intercept of the curve is at (0, 7) so when t = 0, the ball is 7 ft above the ground. Therefore, the ball is thrown from an initial height of 7 feet.
The maximum point of the curve is (0.9, 19.3) which means the maximum height is 19.3 feet is reached after 0.9 seconds.
Finally, the curve intercepts the x-axis at t = 2, which means at 2 s the ball's height is zero, i.e. it hits the ground at 2 s.
